(4+9i)(4-9i)=(4+9i)(4-9i)

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Solution for (4+9i)(4-9i)=(4+9i)(4-9i) equation: 



(4+9i)(4-9i)=(4+9i)(4-9i)

We move all terms to the left:

(4+9i)(4-9i)-((4+9i)(4-9i))=0

We add all the numbers together, and all the variables

(9i+4)(-9i+4)-((9i+4)(-9i+4))=0

We multiply parentheses ..

(-81i^2+36i-36i+16)-((-81i^2+36i-36i+16))=0



We calculate terms in parentheses: -((-81i^2+36i-36i+16)), so:

(-81i^2+36i-36i+16)

We get rid of parentheses

-81i^2+36i-36i+16

We add all the numbers together, and all the variables

-81i^2+16

Back to the equation:

-(-81i^2+16)



We get rid of parentheses

-81i^2+81i^2+36i-36i+16-16=0

We add all the numbers together, and all the variables

=0

i=0/1

i=0

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