(4+i)+(2-i)-(1-i)=0

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Solution for (4+i)+(2-i)-(1-i)=0 equation: 



(4+i)+(2-i)-(1-i)=0

We add all the numbers together, and all the variables

(i+4)+(-1i+2)-(-1i+1)=0

We get rid of parentheses

i-1i+1i+4+2-1=0

We add all the numbers together, and all the variables

i+5=0

We move all terms containing i to the left, all other terms to the right

i=-5

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