(4+i)z=-3+2i

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Solution for (4+i)z=-3+2i equation:


Simplifying
(4 + i) * z = -3 + 2i

Reorder the terms for easier multiplication:
z(4 + i) = -3 + 2i
(4 * z + i * z) = -3 + 2i

Reorder the terms:
(iz + 4z) = -3 + 2i
(iz + 4z) = -3 + 2i

Solving
iz + 4z = -3 + 2i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-2i' to each side of the equation.
iz + -2i + 4z = -3 + 2i + -2i

Reorder the terms:
-2i + iz + 4z = -3 + 2i + -2i

Combine like terms: 2i + -2i = 0
-2i + iz + 4z = -3 + 0
-2i + iz + 4z = -3

Add '-4z' to each side of the equation.
-2i + iz + 4z + -4z = -3 + -4z

Combine like terms: 4z + -4z = 0
-2i + iz + 0 = -3 + -4z
-2i + iz = -3 + -4z

Reorder the terms:
3 + -2i + iz + 4z = -3 + -4z + 3 + 4z

Reorder the terms:
3 + -2i + iz + 4z = -3 + 3 + -4z + 4z

Combine like terms: -3 + 3 = 0
3 + -2i + iz + 4z = 0 + -4z + 4z
3 + -2i + iz + 4z = -4z + 4z

Combine like terms: -4z + 4z = 0
3 + -2i + iz + 4z = 0

The solution to this equation could not be determined.

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