(4+i)z=2-5i

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Solution for (4+i)z=2-5i equation:


Simplifying
(4 + i) * z = 2 + -5i

Reorder the terms for easier multiplication:
z(4 + i) = 2 + -5i
(4 * z + i * z) = 2 + -5i

Reorder the terms:
(iz + 4z) = 2 + -5i
(iz + 4z) = 2 + -5i

Solving
iz + 4z = 2 + -5i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '5i' to each side of the equation.
iz + 5i + 4z = 2 + -5i + 5i

Reorder the terms:
5i + iz + 4z = 2 + -5i + 5i

Combine like terms: -5i + 5i = 0
5i + iz + 4z = 2 + 0
5i + iz + 4z = 2

Add '-4z' to each side of the equation.
5i + iz + 4z + -4z = 2 + -4z

Combine like terms: 4z + -4z = 0
5i + iz + 0 = 2 + -4z
5i + iz = 2 + -4z

Reorder the terms:
-2 + 5i + iz + 4z = 2 + -4z + -2 + 4z

Reorder the terms:
-2 + 5i + iz + 4z = 2 + -2 + -4z + 4z

Combine like terms: 2 + -2 = 0
-2 + 5i + iz + 4z = 0 + -4z + 4z
-2 + 5i + iz + 4z = -4z + 4z

Combine like terms: -4z + 4z = 0
-2 + 5i + iz + 4z = 0

The solution to this equation could not be determined.

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