(4+u)(2u+3)=0

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Solution for (4+u)(2u+3)=0 equation:


Simplifying
(4 + u)(2u + 3) = 0

Reorder the terms:
(4 + u)(3 + 2u) = 0

Multiply (4 + u) * (3 + 2u)
(4(3 + 2u) + u(3 + 2u)) = 0
((3 * 4 + 2u * 4) + u(3 + 2u)) = 0
((12 + 8u) + u(3 + 2u)) = 0
(12 + 8u + (3 * u + 2u * u)) = 0
(12 + 8u + (3u + 2u2)) = 0

Combine like terms: 8u + 3u = 11u
(12 + 11u + 2u2) = 0

Solving
12 + 11u + 2u2 = 0

Solving for variable 'u'.

Factor a trinomial.
(4 + u)(3 + 2u) = 0

Subproblem 1

Set the factor '(4 + u)' equal to zero and attempt to solve: Simplifying 4 + u = 0 Solving 4 + u = 0 Move all terms containing u to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + u = 0 + -4 Combine like terms: 4 + -4 = 0 0 + u = 0 + -4 u = 0 + -4 Combine like terms: 0 + -4 = -4 u = -4 Simplifying u = -4

Subproblem 2

Set the factor '(3 + 2u)' equal to zero and attempt to solve: Simplifying 3 + 2u = 0 Solving 3 + 2u = 0 Move all terms containing u to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + 2u = 0 + -3 Combine like terms: 3 + -3 = 0 0 + 2u = 0 + -3 2u = 0 + -3 Combine like terms: 0 + -3 = -3 2u = -3 Divide each side by '2'. u = -1.5 Simplifying u = -1.5

Solution

u = {-4, -1.5}

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