(4+v)(3v-1)=04+v)(3v-1)=0

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Solution for (4+v)(3v-1)=04+v)(3v-1)=0 equation: 



(4+v)(3v-1)=04+v)(3v-1)=0

We move all terms to the left:

(4+v)(3v-1)-(04+v)(3v-1))=0

We add all the numbers together, and all the variables

(v+4)(3v-1)-(v+4)(3v-1))=0

We multiply parentheses ..

(+3v^2-1v+12v-4)-(+3v^2-1v+12v-4))=0

We get rid of parentheses

3v^2-3v^2-1v+12v+1v-12v-4+4)=0

We add all the numbers together, and all the variables

=0

v=0/1

v=0

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