(4+x)(16+x)/16+x=1(16+x)/2

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Solution for (4+x)(16+x)/16+x=1(16+x)/2 equation: 



(4+x)(16+x)/16+x=1(16+x)/2

We move all terms to the left:

(4+x)(16+x)/16+x-(1(16+x)/2)=0

We add all the numbers together, and all the variables

(x+4)(x+16)/16+x-(1(x+16)/2)=0

We add all the numbers together, and all the variables

x+(x+4)(x+16)/16-(1(x+16)/2)=0

We multiply parentheses ..

(+x^2+16x+4x+64)/16+x-(1(x+16)/2)=0

We calculate fractions


x+(x^2+20x)/()+(-(1(x+16)*16)/()=0



We calculate terms in parentheses: +(-(1(x+16)*16)/(), so:

-(1(x+16)*16)/(

We multiply all the terms by the denominator


-(1(x+16)*16)



We calculate terms in parentheses: -(1(x+16)*16), so:

1(x+16)*16

We multiply parentheses

16x+256

Back to the equation:

-(16x+256)



We get rid of parentheses

-16x-256

Back to the equation:

+(-16x-256)



We get rid of parentheses

x+(x^2+20x)/()-16x-256=0

We multiply all the terms by the denominator


x*()+(x^2+20x)-16x*()-256*()=0

We add all the numbers together, and all the variables

x*()+(x^2+20x)-16x*()=0

We get rid of parentheses

x^2+x*()+20x-16x*()=0

We add all the numbers together, and all the variables

x^2+20x+x*()-16x*()=0

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