(4+x)(5+x)/(2+x)(7-x)=1

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Solution for (4+x)(5+x)/(2+x)(7-x)=1 equation: 



(4+x)(5+x)/(2+x)(7-x)=1

We move all terms to the left:

(4+x)(5+x)/(2+x)(7-x)-(1)=0



Domain of the equation: (2+x)(7-x)!=0

We move all terms containing x to the left, all other terms to the right

x)(7-x!=-2

x∈R



We add all the numbers together, and all the variables

(x+4)(x+5)/(x+2)(-1x+7)-1=0

We multiply parentheses ..

(+x^2+5x+4x+20)/(x+2)(-1x+7)-1=0

We multiply all the terms by the denominator


(+x^2+5x+4x+20)-1*(x+2)(-1x+7)=0

We get rid of parentheses

x^2+5x+4x-1*(x+2)(-1x+7)+20=0

We multiply parentheses ..

x^2-1*(-1x^2+7x-2x+14)+5x+4x+20=0

We add all the numbers together, and all the variables

x^2-1*(-1x^2+7x-2x+14)+9x+20=0

We move all terms containing x to the left, all other terms to the right

x^2-1*(-1x^2+7x-2x+14)+9x=-20

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