(4+x)(5+x)/(2+x)(7-x)=1

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Solution for (4+x)(5+x)/(2+x)(7-x)=1 equation:



(4+x)(5+x)/(2+x)(7-x)=1
We move all terms to the left:
(4+x)(5+x)/(2+x)(7-x)-(1)=0
Domain of the equation: (2+x)(7-x)!=0
We move all terms containing x to the left, all other terms to the right
x)(7-x!=-2
x∈R
We add all the numbers together, and all the variables
(x+4)(x+5)/(x+2)(-1x+7)-1=0
We multiply parentheses ..
(+x^2+5x+4x+20)/(x+2)(-1x+7)-1=0
We multiply all the terms by the denominator
(+x^2+5x+4x+20)-1*(x+2)(-1x+7)=0
We get rid of parentheses
x^2+5x+4x-1*(x+2)(-1x+7)+20=0
We multiply parentheses ..
x^2-1*(-1x^2+7x-2x+14)+5x+4x+20=0
We add all the numbers together, and all the variables
x^2-1*(-1x^2+7x-2x+14)+9x+20=0
We move all terms containing x to the left, all other terms to the right
x^2-1*(-1x^2+7x-2x+14)+9x=-20

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