(4+x)(5-x)/(2+x)(7-x)=-1

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Solution for (4+x)(5-x)/(2+x)(7-x)=-1 equation: 



(4+x)(5-x)/(2+x)(7-x)=-1

We move all terms to the left:

(4+x)(5-x)/(2+x)(7-x)-(-1)=0



Domain of the equation: (2+x)(7-x)!=0

We move all terms containing x to the left, all other terms to the right

x)(7-x!=-2

x∈R



We add all the numbers together, and all the variables

(x+4)(-1x+5)/(x+2)(-1x+7)-(-1)=0

We add all the numbers together, and all the variables

(x+4)(-1x+5)/(x+2)(-1x+7)+1=0

We multiply parentheses ..

(-1x^2+5x-4x+20)/(x+2)(-1x+7)+1=0

We multiply all the terms by the denominator


(-1x^2+5x-4x+20)+1*(x+2)(-1x+7)=0

We get rid of parentheses

-1x^2+5x-4x+1*(x+2)(-1x+7)+20=0

We multiply parentheses ..

-1x^2+1*(-1x^2+7x-2x+14)+5x-4x+20=0

We add all the numbers together, and all the variables

-1x^2+1*(-1x^2+7x-2x+14)+x+20=0

We move all terms containing x to the left, all other terms to the right

-1x^2+1*(-1x^2+7x-2x+14)+x=-20

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