(4+x)/8=(2-x)/4

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Solution for (4+x)/8=(2-x)/4 equation: 



(4+x)/8=(2-x)/4

We move all terms to the left:

(4+x)/8-((2-x)/4)=0

We add all the numbers together, and all the variables

(x+4)/8-((-1x+2)/4)=0

We calculate fractions


x/()+(-((-1x+2)*8)/()=0



We calculate terms in parentheses: +(-((-1x+2)*8)/(), so:

-((-1x+2)*8)/(

We multiply all the terms by the denominator


-((-1x+2)*8)



We calculate terms in parentheses: -((-1x+2)*8), so:

(-1x+2)*8

We multiply parentheses

-8x+16

Back to the equation:

-(-8x+16)



We get rid of parentheses

8x-16

Back to the equation:

+(8x-16)



We get rid of parentheses

x/()+8x-16=0

We multiply all the terms by the denominator


x+8x*()-16*()=0

We add all the numbers together, and all the variables

x+8x*()=0

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