(4+x)/8=(2x-9)/3

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Solution for (4+x)/8=(2x-9)/3 equation: 



(4+x)/8=(2x-9)/3

We move all terms to the left:

(4+x)/8-((2x-9)/3)=0

We add all the numbers together, and all the variables

(x+4)/8-((2x-9)/3)=0

We calculate fractions


x/()+(-((2x-9)*8)/()=0



We calculate terms in parentheses: +(-((2x-9)*8)/(), so:

-((2x-9)*8)/(

We multiply all the terms by the denominator


-((2x-9)*8)



We calculate terms in parentheses: -((2x-9)*8), so:

(2x-9)*8

We multiply parentheses

16x-72

Back to the equation:

-(16x-72)



We get rid of parentheses

-16x+72

Back to the equation:

+(-16x+72)



We get rid of parentheses

x/()-16x+72=0

We multiply all the terms by the denominator


x-16x*()+72*()=0

We add all the numbers together, and all the variables

x-16x*()=0

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