(4+x)2+(3-x2)4=66

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Solution for (4+x)2+(3-x2)4=66 equation: 



(4+x)2+(3-x2)4=66

We move all terms to the left:

(4+x)2+(3-x2)4-(66)=0

We add all the numbers together, and all the variables

(-1x^2+3)4+(x+4)2-66=0

We multiply parentheses

-4x^2+2x+12+8-66=0

We add all the numbers together, and all the variables

-4x^2+2x-46=0

a = -4; b = 2; c = -46;
Δ = b2-4ac
Δ = 22-4·(-4)·(-46)
Δ = -732
Delta is less than zero, so there is no solution for the equation

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