(4+y)(2y-7)=0

Solution for (4+y)(2y-7)=0 equation:

(4+y)(2y-7)=0

We add all the numbers together, and all the variables

(y+4)(2y-7)=0

We multiply parentheses ..

(+2y^2-7y+8y-28)=0

We get rid of parentheses

2y^2-7y+8y-28=0

We add all the numbers together, and all the variables

2y^2+y-28=0

a = 2; b = 1; c = -28;
Δ = b2-4ac
Δ = 12-4·2·(-28)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-15}{2*2}=\frac{-16}{4}
=-4
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+15}{2*2}=\frac{14}{4}
=3+1/2
$