(4+y)(4y+6)=0

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Solution for (4+y)(4y+6)=0 equation:



(4+y)(4y+6)=0
We add all the numbers together, and all the variables
(y+4)(4y+6)=0
We multiply parentheses ..
(+4y^2+6y+16y+24)=0
We get rid of parentheses
4y^2+6y+16y+24=0
We add all the numbers together, and all the variables
4y^2+22y+24=0
a = 4; b = 22; c = +24;
Δ = b2-4ac
Δ = 222-4·4·24
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-10}{2*4}=\frac{-32}{8} =-4 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+10}{2*4}=\frac{-12}{8} =-1+1/2 $

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