(4+y)+2=(y+4)+2

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Solution for (4+y)+2=(y+4)+2 equation:


Simplifying
(4 + y) + 2 = (y + 4) + 2

Remove parenthesis around (4 + y)
4 + y + 2 = (y + 4) + 2

Reorder the terms:
4 + 2 + y = (y + 4) + 2

Combine like terms: 4 + 2 = 6
6 + y = (y + 4) + 2

Reorder the terms:
6 + y = (4 + y) + 2

Remove parenthesis around (4 + y)
6 + y = 4 + y + 2

Reorder the terms:
6 + y = 4 + 2 + y

Combine like terms: 4 + 2 = 6
6 + y = 6 + y

Add '-6' to each side of the equation.
6 + -6 + y = 6 + -6 + y

Combine like terms: 6 + -6 = 0
0 + y = 6 + -6 + y
y = 6 + -6 + y

Combine like terms: 6 + -6 = 0
y = 0 + y
y = y

Add '-1y' to each side of the equation.
y + -1y = y + -1y

Combine like terms: y + -1y = 0
0 = y + -1y

Combine like terms: y + -1y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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