(4+y)-7=3(y-1)+y

Solution for (4+y)-7=3(y-1)+y equation:

(4+y)-7=3(y-1)+y

We move all terms to the left:

(4+y)-7-(3(y-1)+y)=0

We add all the numbers together, and all the variables

(y+4)-(3(y-1)+y)-7=0

We get rid of parentheses

y-(3(y-1)+y)+4-7=0


We calculate terms in parentheses: -(3(y-1)+y), so:

3(y-1)+y

We add all the numbers together, and all the variables

y+3(y-1)

We multiply parentheses

y+3y-3

We add all the numbers together, and all the variables

4y-3

Back to the equation:

-(4y-3)


We add all the numbers together, and all the variables

y-(4y-3)-3=0

We get rid of parentheses

y-4y+3-3=0

We add all the numbers together, and all the variables

-3y=0

y=0/-3

y=0