(4+z)(5z+6)=0

Solution for (4+z)(5z+6)=0 equation:

(4+z)(5z+6)=0

We add all the numbers together, and all the variables

(z+4)(5z+6)=0

We multiply parentheses ..

(+5z^2+6z+20z+24)=0

We get rid of parentheses

5z^2+6z+20z+24=0

We add all the numbers together, and all the variables

5z^2+26z+24=0

a = 5; b = 26; c = +24;
Δ = b2-4ac
Δ = 262-4·5·24
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{196}=14$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-14}{2*5}=\frac{-40}{10}
=-4
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+14}{2*5}=\frac{-12}{10}
=-1+1/5
$