(4,1+3,8i)(4,1-3,8i)=

Solution for (4,1+3,8i)(4,1-3,8i)= equation:

(4.1+3.8i)(4.1-3.8i)=

We move all terms to the left:

(4.1+3.8i)(4.1-3.8i)-()=0

We add all the numbers together, and all the variables

(3.8i+4.1)(-3.8i+4.1)-()=0

We add all the numbers together, and all the variables

(3.8i+4.1)(-3.8i+4.1)=0

We multiply parentheses ..

(-9i^2+12.3i-12.3i+16.81)=0

We get rid of parentheses

-9i^2+12.3i-12.3i+16.81=0

We add all the numbers together, and all the variables

-9i^2+16.81=0

a = -9; b = 0; c = +16.81;
Δ = b2-4ac
Δ = 02-4·(-9)·16.81
Δ = 605.16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{605.16}}{2*-9}=\frac{0-\sqrt{605.16}}{-18}
=-\frac{\sqrt{}}{-18}
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{605.16}}{2*-9}=\frac{0+\sqrt{605.16}}{-18}
=\frac{\sqrt{}}{-18}
$