(4-19)+(3x+1)=122

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Solution for (4-19)+(3x+1)=122 equation:



(4-19)+(3x+1)=122
We move all terms to the left:
(4-19)+(3x+1)-(122)=0
determiningTheFunctionDomain (3x+1)-122+(4-19)=0
We add all the numbers together, and all the variables
(3x+1)-122+(-15)=0
We add all the numbers together, and all the variables
(3x+1)-137=0
We get rid of parentheses
3x+1-137=0
We add all the numbers together, and all the variables
3x-136=0
We move all terms containing x to the left, all other terms to the right
3x=136
x=136/3
x=45+1/3

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