(4-2(8x+3))=3(x-2)

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Solution for (4-2(8x+3))=3(x-2) equation: 



(4-2(8x+3))=3(x-2)

We move all terms to the left:

(4-2(8x+3))-(3(x-2))=0



We calculate terms in parentheses: +(4-2(8x+3)), so:

4-2(8x+3)

determiningTheFunctionDomain
-2(8x+3)+4

We multiply parentheses

-16x-6+4

We add all the numbers together, and all the variables

-16x-2

Back to the equation:

+(-16x-2)





We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We get rid of parentheses

-16x-3x-2+6=0

We add all the numbers together, and all the variables

-19x+4=0

We move all terms containing x to the left, all other terms to the right

-19x=-4

x=-4/-19

x=4/19

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