(4-2i)(3+i)=

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Solution for (4-2i)(3+i)= equation:


Simplifying
(4 + -2i)(3 + i) = 0

Multiply (4 + -2i) * (3 + i)
(4(3 + i) + -2i * (3 + i)) = 0
((3 * 4 + i * 4) + -2i * (3 + i)) = 0
((12 + 4i) + -2i * (3 + i)) = 0
(12 + 4i + (3 * -2i + i * -2i)) = 0
(12 + 4i + (-6i + -2i2)) = 0

Combine like terms: 4i + -6i = -2i
(12 + -2i + -2i2) = 0

Solving
12 + -2i + -2i2 = 0

Solving for variable 'i'.

Factor out the Greatest Common Factor (GCF), '2'.
2(6 + -1i + -1i2) = 0

Factor a trinomial.
2((2 + -1i)(3 + i)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(2 + -1i)' equal to zero and attempt to solve: Simplifying 2 + -1i = 0 Solving 2 + -1i = 0 Move all terms containing i to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1i = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1i = 0 + -2 -1i = 0 + -2 Combine like terms: 0 + -2 = -2 -1i = -2 Divide each side by '-1'. i = 2 Simplifying i = 2

Subproblem 2

Set the factor '(3 + i)' equal to zero and attempt to solve: Simplifying 3 + i = 0 Solving 3 + i = 0 Move all terms containing i to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + i = 0 + -3 Combine like terms: 3 + -3 = 0 0 + i = 0 + -3 i = 0 + -3 Combine like terms: 0 + -3 = -3 i = -3 Simplifying i = -3

Solution

i = {2, -3}

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