(4-2r)=2(r+5)

Solution for (4-2r)=2(r+5) equation:

(4-2r)=2(r+5)

We move all terms to the left:

(4-2r)-(2(r+5))=0

We add all the numbers together, and all the variables

(-2r+4)-(2(r+5))=0

We get rid of parentheses

-2r-(2(r+5))+4=0


We calculate terms in parentheses: -(2(r+5)), so:

2(r+5)

We multiply parentheses

2r+10

Back to the equation:

-(2r+10)


We get rid of parentheses

-2r-2r-10+4=0

We add all the numbers together, and all the variables

-4r-6=0

We move all terms containing r to the left, all other terms to the right

-4r=6

r=6/-4

r=-1+1/2