(4-2u)(3+u)=

Solution for (4-2u)(3+u)= equation:

Simplifying
(4 + -2u)(3 + u) = 0

Multiply (4 + -2u) * (3 + u)
(4(3 + u) + -2u * (3 + u)) = 0
((3 * 4 + u * 4) + -2u * (3 + u)) = 0
((12 + 4u) + -2u * (3 + u)) = 0
(12 + 4u + (3 * -2u + u * -2u)) = 0
(12 + 4u + (-6u + -2u2)) = 0

Combine like terms: 4u + -6u = -2u
(12 + -2u + -2u2) = 0

Solving
12 + -2u + -2u2 = 0

Solving for variable 'u'.

Factor out the Greatest Common Factor (GCF), '2'.
2(6 + -1u + -1u2) = 0

Factor a trinomial.
2((2 + -1u)(3 + u)) = 0

Ignore the factor 2.
Subproblem 1
Set the factor '(2 + -1u)' equal to zero and attempt to solve:

Simplifying
2 + -1u = 0

Solving
2 + -1u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1u = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1u = 0 + -2
-1u = 0 + -2

Combine like terms: 0 + -2 = -2
-1u = -2

Divide each side by '-1'.
u = 2

Simplifying
u = 2
Subproblem 2
Set the factor '(3 + u)' equal to zero and attempt to solve:

Simplifying
3 + u = 0

Solving
3 + u = 0

Move all terms containing u to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + u = 0 + -3

Combine like terms: 3 + -3 = 0
0 + u = 0 + -3
u = 0 + -3

Combine like terms: 0 + -3 = -3
u = -3

Simplifying
u = -3
Solution
u = {2, -3}