(4-2x)(x-8)=0

Solution for (4-2x)(x-8)=0 equation:

(4-2x)(x-8)=0

We add all the numbers together, and all the variables

(-2x+4)(x-8)=0

We multiply parentheses ..

(-2x^2+16x+4x-32)=0

We get rid of parentheses

-2x^2+16x+4x-32=0

We add all the numbers together, and all the variables

-2x^2+20x-32=0

a = -2; b = 20; c = -32;
Δ = b2-4ac
Δ = 202-4·(-2)·(-32)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-12}{2*-2}=\frac{-32}{-4}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+12}{2*-2}=\frac{-8}{-4}
=+2
$