(4-2x)*(4-2x)=0

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Solution for (4-2x)*(4-2x)=0 equation: 



(4-2x)(4-2x)=0

We add all the numbers together, and all the variables

(-2x+4)(-2x+4)=0

We multiply parentheses ..

(+4x^2-8x-8x+16)=0

We get rid of parentheses

4x^2-8x-8x+16=0

We add all the numbers together, and all the variables

4x^2-16x+16=0

a = 4; b = -16; c = +16;
Δ = b2-4ac
Δ = -162-4·4·16
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{16}{8}=2$

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