(4-3i)+(9+2i)=13-i

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Solution for (4-3i)+(9+2i)=13-i equation:


Simplifying
(4 + -3i) + (9 + 2i) = 13 + -1i

Remove parenthesis around (4 + -3i)
4 + -3i + (9 + 2i) = 13 + -1i

Remove parenthesis around (9 + 2i)
4 + -3i + 9 + 2i = 13 + -1i

Reorder the terms:
4 + 9 + -3i + 2i = 13 + -1i

Combine like terms: 4 + 9 = 13
13 + -3i + 2i = 13 + -1i

Combine like terms: -3i + 2i = -1i
13 + -1i = 13 + -1i

Add '-13' to each side of the equation.
13 + -13 + -1i = 13 + -13 + -1i

Combine like terms: 13 + -13 = 0
0 + -1i = 13 + -13 + -1i
-1i = 13 + -13 + -1i

Combine like terms: 13 + -13 = 0
-1i = 0 + -1i
-1i = -1i

Add 'i' to each side of the equation.
-1i + i = -1i + i

Combine like terms: -1i + i = 0
0 = -1i + i

Combine like terms: -1i + i = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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