(4-3x)(10-9x)=0

Solution for (4-3x)(10-9x)=0 equation:

(4-3x)(10-9x)=0

We add all the numbers together, and all the variables

(-3x+4)(-9x+10)=0

We multiply parentheses ..

(+27x^2-30x-36x+40)=0

We get rid of parentheses

27x^2-30x-36x+40=0

We add all the numbers together, and all the variables

27x^2-66x+40=0

a = 27; b = -66; c = +40;
Δ = b2-4ac
Δ = -662-4·27·40
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-66)-6}{2*27}=\frac{60}{54}
=1+1/9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-66)+6}{2*27}=\frac{72}{54}
=1+1/3
$