(4-6x)-41=(9x-3)

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Solution for (4-6x)-41=(9x-3) equation: 



(4-6x)-41=(9x-3)

We move all terms to the left:

(4-6x)-41-((9x-3))=0

We add all the numbers together, and all the variables

(-6x+4)-((9x-3))-41=0

We get rid of parentheses

-6x-((9x-3))+4-41=0



We calculate terms in parentheses: -((9x-3)), so:

(9x-3)

We get rid of parentheses

9x-3

Back to the equation:

-(9x-3)



We add all the numbers together, and all the variables

-6x-(9x-3)-37=0

We get rid of parentheses

-6x-9x+3-37=0

We add all the numbers together, and all the variables

-15x-34=0

We move all terms containing x to the left, all other terms to the right

-15x=34

x=34/-15

x=-2+4/15

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