(4-7i)(6-8i)=0

Solution for (4-7i)(6-8i)=0 equation:

(4-7i)(6-8i)=0

We add all the numbers together, and all the variables

(-7i+4)(-8i+6)=0

We multiply parentheses ..

(+56i^2-42i-32i+24)=0

We get rid of parentheses

56i^2-42i-32i+24=0

We add all the numbers together, and all the variables

56i^2-74i+24=0

a = 56; b = -74; c = +24;
Δ = b2-4ac
Δ = -742-4·56·24
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-74)-10}{2*56}=\frac{64}{112}
=4/7
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-74)+10}{2*56}=\frac{84}{112}
=3/4
$