(4-v)(3v-2)=0

Solution for (4-v)(3v-2)=0 equation:

(4-v)(3v-2)=0

We add all the numbers together, and all the variables

(-1v+4)(3v-2)=0

We multiply parentheses ..

(-3v^2+2v+12v-8)=0

We get rid of parentheses

-3v^2+2v+12v-8=0

We add all the numbers together, and all the variables

-3v^2+14v-8=0

a = -3; b = 14; c = -8;
Δ = b2-4ac
Δ = 142-4·(-3)·(-8)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-10}{2*-3}=\frac{-24}{-6}
=+4
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+10}{2*-3}=\frac{-4}{-6}
=2/3
$