(4-v)(5v-7)=0

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Solution for (4-v)(5v-7)=0 equation:



(4-v)(5v-7)=0
We add all the numbers together, and all the variables
(-1v+4)(5v-7)=0
We multiply parentheses ..
(-5v^2+7v+20v-28)=0
We get rid of parentheses
-5v^2+7v+20v-28=0
We add all the numbers together, and all the variables
-5v^2+27v-28=0
a = -5; b = 27; c = -28;
Δ = b2-4ac
Δ = 272-4·(-5)·(-28)
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-13}{2*-5}=\frac{-40}{-10} =+4 $
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+13}{2*-5}=\frac{-14}{-10} =1+2/5 $

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