(4-w)(4w+3)=0

Solution for (4-w)(4w+3)=0 equation:

(4-w)(4w+3)=0

We add all the numbers together, and all the variables

(-1w+4)(4w+3)=0

We multiply parentheses ..

(-4w^2-3w+16w+12)=0

We get rid of parentheses

-4w^2-3w+16w+12=0

We add all the numbers together, and all the variables

-4w^2+13w+12=0

a = -4; b = 13; c = +12;
Δ = b2-4ac
Δ = 132-4·(-4)·12
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{361}=19$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-19}{2*-4}=\frac{-32}{-8}
=+4
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+19}{2*-4}=\frac{6}{-8}
=-3/4
$