(4-x)(1/2x-4)=0

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Solution for (4-x)(1/2x-4)=0 equation: 



(4-x)(1/2x-4)=0



Domain of the equation: 2x-4)!=0

x∈R



We add all the numbers together, and all the variables

(-1x+4)(1/2x-4)=0

We multiply parentheses ..

(-1x^2+4x+4x-16)=0

We get rid of parentheses

-1x^2+4x+4x-16=0

We add all the numbers together, and all the variables

-1x^2+8x-16=0

a = -1; b = 8; c = -16;
Δ = b2-4ac
Δ = 82-4·(-1)·(-16)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-8}{-2}=+4$

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