(4-x)(11-3x)=0

Solution for (4-x)(11-3x)=0 equation:

(4-x)(11-3x)=0

We add all the numbers together, and all the variables

(-1x+4)(-3x+11)=0

We multiply parentheses ..

(+3x^2-11x-12x+44)=0

We get rid of parentheses

3x^2-11x-12x+44=0

We add all the numbers together, and all the variables

3x^2-23x+44=0

a = 3; b = -23; c = +44;
Δ = b2-4ac
Δ = -232-4·3·44
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-1}{2*3}=\frac{22}{6}
=3+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+1}{2*3}=\frac{24}{6}
=4
$