(4-x)(2x-8)=0

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Solution for (4-x)(2x-8)=0 equation: 



(4-x)(2x-8)=0

We add all the numbers together, and all the variables

(-1x+4)(2x-8)=0

We multiply parentheses ..

(-2x^2+8x+8x-32)=0

We get rid of parentheses

-2x^2+8x+8x-32=0

We add all the numbers together, and all the variables

-2x^2+16x-32=0

a = -2; b = 16; c = -32;
Δ = b2-4ac
Δ = 162-4·(-2)·(-32)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-16}{-4}=+4$

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