(4-x)(3x+6)=0

Solution for (4-x)(3x+6)=0 equation:

(4-x)(3x+6)=0

We add all the numbers together, and all the variables

(-1x+4)(3x+6)=0

We multiply parentheses ..

(-3x^2-6x+12x+24)=0

We get rid of parentheses

-3x^2-6x+12x+24=0

We add all the numbers together, and all the variables

-3x^2+6x+24=0

a = -3; b = 6; c = +24;
Δ = b2-4ac
Δ = 62-4·(-3)·24
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-18}{2*-3}=\frac{-24}{-6}
=+4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+18}{2*-3}=\frac{12}{-6}
=-2
$