(4-x)/5=(x+4)/2

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Solution for (4-x)/5=(x+4)/2 equation:



(4-x)/5=(x+4)/2
We move all terms to the left:
(4-x)/5-((x+4)/2)=0
We add all the numbers together, and all the variables
(-1x+4)/5-((x+4)/2)=0
We calculate fractions
(-x)/()+(-((x+4)*5)/()=0
We calculate terms in parentheses: +(-((x+4)*5)/(), so:
-((x+4)*5)/(
We multiply all the terms by the denominator
-((x+4)*5)
We calculate terms in parentheses: -((x+4)*5), so:
(x+4)*5
We multiply parentheses
5x+20
Back to the equation:
-(5x+20)
We get rid of parentheses
-5x-20
Back to the equation:
+(-5x-20)
We add all the numbers together, and all the variables
(-1x)/()+(-5x-20)=0
We get rid of parentheses
(-1x)/()-5x-20=0
We multiply all the terms by the denominator
(-1x)-5x*()-20*()=0
We add all the numbers together, and all the variables
(-1x)-5x*()=0
We get rid of parentheses
-1x-5x*()=0

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