(4/(x+3))+(2/(x-3))=12/((x+3)(x-3))

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Solution for (4/(x+3))+(2/(x-3))=12/((x+3)(x-3)) equation: 



(4/(x+3))+(2/(x-3))=12/((x+3)(x-3))

We move all terms to the left:

(4/(x+3))+(2/(x-3))-(12/((x+3)(x-3)))=0



Domain of the equation: (x+3))!=0

x∈R





Domain of the equation: (x-3))!=0

x∈R





Domain of the equation: ((x+3)(x-3)))!=0

x∈R



We use the square of the difference formula

x^2+(4/(x+3))+(2/(x-3))+9=0

We calculate fractions


x^2+(4x-12)/((x+3))*x+(2x+6)/((x+3))*x+9=0

We multiply all the terms by the denominator


x^2*((x+3))*x+(4x-12)+(2x+6)+9*((x+3))*x=0

We get rid of parentheses

x^2*((x+3))*x+4x+2x+9*((x+3))*x-12+6=0

We add all the numbers together, and all the variables

x^2*((x+3))*x+6x+9*((x+3))*x-6=0

We move all terms containing x to the left, all other terms to the right

x^2*((x+3))*x+6x+9*((x+3))*x=6

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