(4/(x-1))=((x+1)/12)

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Solution for (4/(x-1))=((x+1)/12) equation: 


D( x )

x-1 = 0

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:1) U (1:+oo)

4/(x-1) = (x+1)/12 // - (x+1)/12

4/(x-1)-((x+1)/12) = 0

4/(x-1)+(-1*(x+1))/12 = 0

(4*12)/(12*(x-1))+(-1*(x+1)*(x-1))/(12*(x-1)) = 0

4*12-1*(x+1)*(x-1) = 0

49-x^2 = 0

(49-x^2)/(12*(x-1)) = 0

(49-x^2)/(12*(x-1)) = 0 // * 12*(x-1)

49-x^2 = 0

-1*x^2 = -49 // : -1

x^2 = 49

x^2 = 49 // ^ 1/2

abs(x) = 7

x = 7 or x = -7

x in { 7, -7 }

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