(4/(y-1))-(1/2)=(3/(y+1))

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Solution for (4/(y-1))-(1/2)=(3/(y+1)) equation:


D( y )

y-1 = 0

y+1 = 0

y-1 = 0

y-1 = 0

y-1 = 0 // + 1

y = 1

y+1 = 0

y+1 = 0

y+1 = 0 // - 1

y = -1

y in (-oo:-1) U (-1:1) U (1:+oo)

4/(y-1)-(1/2) = 3/(y+1) // - 3/(y+1)

4/(y-1)-(3/(y+1))-(1/2) = 0

4/(y-1)-3*(y+1)^-1-1/2 = 0

4/(y-1)-3/(y+1)-1/2 = 0

(2*4*(y+1))/(2*(y-1)*(y+1))+(-3*2*(y-1))/(2*(y-1)*(y+1))+(-1*(y-1)*(y+1))/(2*(y-1)*(y+1)) = 0

2*4*(y+1)-3*2*(y-1)-1*(y-1)*(y+1) = 0

2*y-y^2+1+14 = 0

2*y-y^2+15 = 0

2*y-y^2+15 = 0

2*y-y^2+15 = 0

DELTA = 2^2-(-1*4*15)

DELTA = 64

DELTA > 0

y = (64^(1/2)-2)/(-1*2) or y = (-64^(1/2)-2)/(-1*2)

y = -3 or y = 5

(y+3)*(y-5) = 0

((y+3)*(y-5))/(2*(y-1)*(y+1)) = 0

((y+3)*(y-5))/(2*(y-1)*(y+1)) = 0 // * 2*(y-1)*(y+1)

(y+3)*(y-5) = 0

( y+3 )

y+3 = 0 // - 3

y = -3

( y-5 )

y-5 = 0 // + 5

y = 5

y in { -3, 5 }

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