(4/10x)-4x+(6/5)=(4/5)

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Solution for (4/10x)-4x+(6/5)=(4/5) equation:



(4/10x)-4x+(6/5)=(4/5)
We move all terms to the left:
(4/10x)-4x+(6/5)-((4/5))=0
Domain of the equation: 10x)!=0
x!=0/1
x!=0
x∈R
We add all the numbers together, and all the variables
(+4/10x)-4x+(+6/5)-((+4/5))=0
We add all the numbers together, and all the variables
-4x+(+4/10x)+(+6/5)-((+4/5))=0
We get rid of parentheses
-4x+4/10x+6/5-((+4/5))=0
We calculate fractions
-4x+()/1250x^2+60x/1250x^2+(-((+4*10x)/1250x^2=0
We multiply all the terms by the denominator
-4x*1250x^2+60x+(-((+4*10x)+()=0
We calculate terms in parentheses: +(-((+4*10x)+(), so:
-((+4*10x)+(
We add all the numbers together, and all the variables
60x-4x*1250x^2+(-((+4*10x)+()=0
Wy multiply elements
-5000x^3+60x+(-((+4*10x)+()=0
We calculate terms in parentheses: +(-((+4*10x)+(), so:
-((+4*10x)+(
We do not support expression: x^3

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