(4/2y-1)=7-(3/y)

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Solution for (4/2y-1)=7-(3/y) equation: 



(4/2y-1)=7-(3/y)

We move all terms to the left:

(4/2y-1)-(7-(3/y))=0



Domain of the equation: 2y-1)!=0

y∈R





Domain of the equation: y))!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(4/2y-1)-(7-(+3/y))=0

We get rid of parentheses

4/2y-(7-(+3/y))-1=0

We calculate fractions


4y/2y^2+(-(7-(+3*2y)/2y^2-1=0

We calculate fractions

We do not support eypression: y^4

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