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(4/3(x+2))-2/3x=1/(x+2)
We move all terms to the left:
(4/3(x+2))-2/3x-(1/(x+2))=0
Domain of the equation: 3(x+2))!=0
x∈R
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: (x+2))!=0We calculate fractions
x∈R
((12x^2*())/(3(x+2))*3x*x+(-6x^2x/(3(x+2))*3x*x+(-(1*3(x+2))*3x)/(3(x+2))*3x*x=0
We can not solve this equation
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