(4/3)(5x+1)=8

Solution for (4/3)(5x+1)=8 equation:

(4/3)(5x+1)=8

We move all terms to the left:

(4/3)(5x+1)-(8)=0


Domain of the equation: 3)(5x+1)!=0

x∈R


We add all the numbers together, and all the variables

(+4/3)(5x+1)-8=0

We multiply parentheses ..

(+20x^2+4/3*1)-8=0

We multiply all the terms by the denominator


(+20x^2+4-8*3*1)=0

We get rid of parentheses

20x^2+4-8*3*1=0

We add all the numbers together, and all the variables

20x^2-20=0

a = 20; b = 0; c = -20;
Δ = b2-4ac
Δ = 02-4·20·(-20)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40}{2*20}=\frac{-40}{40}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40}{2*20}=\frac{40}{40}
=1
$