(4/3)(5x-2)=7(x(5x-2))

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Solution for (4/3)(5x-2)=7(x(5x-2)) equation: 



(4/3)(5x-2)=7(x(5x-2))

We move all terms to the left:

(4/3)(5x-2)-(7(x(5x-2)))=0



Domain of the equation: 3)(5x-2)!=0

x∈R



We add all the numbers together, and all the variables

(+4/3)(5x-2)-(7(x(5x-2)))=0

We multiply parentheses ..

(+20x^2+4/3*-2)-(7(x(5x-2)))=0

We multiply all the terms by the denominator


(+20x^2+4-((7(x(5x-2))))*3*-2)=0



We calculate terms in parentheses: +(+20x^2+4-((7(x(5x-2))))*3*-2), so:

+20x^2+4-((7(x(5x-2))))*3*-2

determiningTheFunctionDomain
20x^2-((7(x(5x-2))))*3*+4-2

We add all the numbers together, and all the variables

20x^2-((7(x(5x-2))))*3*+2

Back to the equation:

+(20x^2-((7(x(5x-2))))*3*+2)





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





We calculate terms in parentheses: +(20x^2-((7(x(5x-2))))*3*+2), so:

20x^2-((7(x(5x-2))))*3*+2





							

									
									
									
									
									
									

														
			

			
				

						
				
				
					
			
						
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