(4/3)(x+3)=(3/2x)+2

Solution for (4/3)(x+3)=(3/2x)+2 equation:

(4/3)(x+3)=(3/2x)+2

We move all terms to the left:

(4/3)(x+3)-((3/2x)+2)=0


Domain of the equation: 3)(x+3)!=0

x∈R



Domain of the equation: 2x)+2)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+4/3)(x+3)-((+3/2x)+2)=0

We multiply parentheses ..

(+4x^2+4/3*3)-((+3/2x)+2)=0

We calculate fractions


(4x^2+8x)/18x^2+()/18x^2=0

We multiply all the terms by the denominator


(4x^2+8x)+()=0

We add all the numbers together, and all the variables

(4x^2+8x)=0

We get rid of parentheses

4x^2+8x=0

a = 4; b = 8; c = 0;
Δ = b2-4ac
Δ = 82-4·4·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8}{2*4}=\frac{-16}{8}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8}{2*4}=\frac{0}{8}
=0
$