(4/3)(x+3)=12

Solution for (4/3)(x+3)=12 equation:

(4/3)(x+3)=12

We move all terms to the left:

(4/3)(x+3)-(12)=0


Domain of the equation: 3)(x+3)!=0

x∈R


We add all the numbers together, and all the variables

(+4/3)(x+3)-12=0

We multiply parentheses ..

(+4x^2+4/3*3)-12=0

We multiply all the terms by the denominator


(+4x^2+4-12*3*3)=0

We get rid of parentheses

4x^2+4-12*3*3=0

We add all the numbers together, and all the variables

4x^2-104=0

a = 4; b = 0; c = -104;
Δ = b2-4ac
Δ = 02-4·4·(-104)
Δ = 1664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1664}=\sqrt{64*26}=\sqrt{64}*\sqrt{26}=8\sqrt{26}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{26}}{2*4}=\frac{0-8\sqrt{26}}{8}
=-\frac{8\sqrt{26}}{8}
=-\sqrt{26}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{26}}{2*4}=\frac{0+8\sqrt{26}}{8}
=\frac{8\sqrt{26}}{8}
=\sqrt{26}
$