(4/3)u=48

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Solution for (4/3)u=48 equation:



(4/3)u=48
We move all terms to the left:
(4/3)u-(48)=0
Domain of the equation: 3)u!=0
u!=0/1
u!=0
u∈R
We add all the numbers together, and all the variables
(+4/3)u-48=0
We multiply parentheses
4u^2-48=0
a = 4; b = 0; c = -48;
Δ = b2-4ac
Δ = 02-4·4·(-48)
Δ = 768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{768}=\sqrt{256*3}=\sqrt{256}*\sqrt{3}=16\sqrt{3}$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{3}}{2*4}=\frac{0-16\sqrt{3}}{8} =-\frac{16\sqrt{3}}{8} =-2\sqrt{3} $
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{3}}{2*4}=\frac{0+16\sqrt{3}}{8} =\frac{16\sqrt{3}}{8} =2\sqrt{3} $

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