(4/3)u=48

Solution for (4/3)u=48 equation:

(4/3)u=48

We move all terms to the left:

(4/3)u-(48)=0


Domain of the equation: 3)u!=0

u!=0/1

u!=0

u∈R


We add all the numbers together, and all the variables

(+4/3)u-48=0

We multiply parentheses

4u^2-48=0

a = 4; b = 0; c = -48;
Δ = b2-4ac
Δ = 02-4·4·(-48)
Δ = 768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{768}=\sqrt{256*3}=\sqrt{256}*\sqrt{3}=16\sqrt{3}$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{3}}{2*4}=\frac{0-16\sqrt{3}}{8}
=-\frac{16\sqrt{3}}{8}
=-2\sqrt{3}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{3}}{2*4}=\frac{0+16\sqrt{3}}{8}
=\frac{16\sqrt{3}}{8}
=2\sqrt{3}
$