(4/3)x+(1/3)=(-7/3)

Solution for (4/3)x+(1/3)=(-7/3) equation:

(4/3)x+(1/3)=(-7/3)

We move all terms to the left:

(4/3)x+(1/3)-((-7/3))=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+4/3)x+(+1/3)-((-7/3))=0

We multiply parentheses

4x^2+(+1/3)-((-7/3))=0

We get rid of parentheses

4x^2+1/3-((-7/3))=0

We calculate fractions


4x^2=0

a = 4; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·4·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{8}=0$