(4/3)x-397=603

Solution for (4/3)x-397=603 equation:

(4/3)x-397=603

We move all terms to the left:

(4/3)x-397-(603)=0


Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+4/3)x-397-603=0

We add all the numbers together, and all the variables

(+4/3)x-1000=0

We multiply parentheses

4x^2-1000=0

a = 4; b = 0; c = -1000;
Δ = b2-4ac
Δ = 02-4·4·(-1000)
Δ = 16000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16000}=\sqrt{1600*10}=\sqrt{1600}*\sqrt{10}=40\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{10}}{2*4}=\frac{0-40\sqrt{10}}{8}
=-\frac{40\sqrt{10}}{8}
=-5\sqrt{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{10}}{2*4}=\frac{0+40\sqrt{10}}{8}
=\frac{40\sqrt{10}}{8}
=5\sqrt{10}
$